Saturday, December 22, 2018
'Hkcee Past Paper\r'
'hk?????? FOR TEACHERSââ¬â¢ drug ab routine nevertheless ???????? HONG KONG EXAMINATIONS AND ASSESSMENT AUTHORITY ???????? HONG KONG diploma OF SECONDARY EDUCATION EXAMINATION ??? execute PAPER ?? MATHEMATICS ???? COMPULSORY dampen ??? PAPER 1 ???? (??? ) PROVISIONAL stigma SCHEME This marking schema has been hustling by the Hong Kong Examinations and estimation delegacy for teachersââ¬â¢ reference. Teachers should prompt their students NOT to regard this marking scheme as a set of moulding answers. Our examinations emphasise the testing of understanding, the practical application of knowledge and the use of processing skills.Hence the use of model answers, or anything else which encourages rote memorisation, forget not help students to improve their acquirement nor develop their abilities in addressing and solving problems. The Authority is counting on the co-operation of teachers in this regard. Hong Kong Examinations and Assessment Authority All Rights Reserve d 2012 PP-DSE-MATH-CP 1? 1 ?????? ???? ???????? é ??????? ,???????? ???? ,????????????????????? ,?? ????? ,????????? ,??????????? ,? ??? ,????????????? ,??????????? ???? ,???????????????????????? FOR TEACHERSââ¬â¢ intake only ????????????? ?????????? ?????? ,??????????????? ,????? ? ? ? ? ? , ? ? ? ? ? ? ? ? ? ? ? ? ? , ? ? ? ? ? ? ? ? ? ? ? ? ? ?, ? ? ? ? ? ? ?? ??? ,????? ??? ? ? ? ? ? ? ? ? , ? ? ? ? ? ?? ? ? ? ? ? ? ? ? ? ? ? ?? ?? ??? ,????? ?? ? ? ? ? ? ? ? ? ?, ? ? ? ? ? ?? ? ? ? ? ? ? ? ? ? ? ? ? ? :???? ????? ???? ??????????? ,??????????? ????? ,???????????????? ????????? ,???????????????????? ,????????????????? ??????? ,???????????????????????????? ,?? ?????????????????? ,???????????? ,??????? ? ) ? ? ? ? ? ? ( ?? ? ? ? ? ? ? ? ? ? ? , ?? ? ? ? ? ? ? ? ? ? ? ? ,????????????? ,???????????????????????? ,??????????????????????????? ,?????????? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?? ? ?? ? ? ? ;??????? ?? ? ;????????? ?? ? ?????????? ,?????? ?????????? ? ? ? ? ? ? ? ? ? ? ?? ) ? ? ? ? ? ? ? ? ? ? ? ? (???? ? ? ? ? ? ? ? ? ? ?? ,???????????????? ,???? ,?????????????? ?????????????????? ,???????????????? ,??? ???????? ,??????????????? ,????? ;? ???????????????? ,????????????????????? ??? ,???? ,???????????????????? ,????????? a. M A (u) 1 PP-DSE-MATH-CP 1? 2 8. 1. 3. 4. 7. 5. 2. 6. c. d. b. ?????? ?????? u-1 pp-1 M (1) 1 A (pp) M (2) ???????? ?? ???? ??? ?????? u FOR TEACHERSââ¬â¢ substance abuse solitary(prenominal) FOR TEACHERSââ¬â¢ enjoyment only when pp 1 1 1 (1) (1) A (2) (2) ?????? (m 5 n ? 2 ) 6 m 4 n ? 3 m 30 n ? 2 FOR TEACHERSââ¬â¢ using up however 1. = = m 4 n ? 3 m30 ? 4 n12 ? 3 1M 1M 1A ———-(3) m 26 = n9 2. 1M 1M 1A 3ab = 2b ? 5 2b ? 5 a= 3b 1M 1M 1A ———-(3) 3. (a) 9 x 2 ? 42 xy + 49 y 2 1A (b) 9 x 2 ? 42 xy + 49 y 2 ? 6 x + 14 y 1M 1A ———-(3) PP-DSE-MATH-CP 1? 3 ?????? FOR TEACHERSââ¬â¢ utilize however ??? = (3x ? 7 y ) 2 ? 2(3x ? 7 y ) = (3x ? 7 y )(3 x ? 7 y ? 2) ??? = (3x ? 7 y ) 2 ? 6 x + 14 y ??? = (3x ? 7 y ) 2 ??? 5+b 3b 3b ? (5 + b) a= 3b 2b ? 5 a= 3b a = 1? ???? ?? ? 5+b = 3b 1? a 5 + b = 3b(1 ? a) ??? ???? ?? ? 5+b = 3b 1? a 5 + b = 3b(1 ? a) 5 + b = 3b ? 3ab 3b(1 ? a) a 3b(1 ? a) a (a) ? ap = a p ? q a ? (ab) p = a pb p ?? (a p )q = a pq ap 1 = q? p q a a ? ? ? ? ?????? 4. $x x (80%) = 360 (1 + 30%) 360(1. 3) x= 0. 8 x = 585 FOR TEACHERSââ¬â¢ engagement simply pp? 1 1M + 1M 1M+1M+1A 1A u? 1 = 1M+1M+1A 1M + 1M 1A u? 1 ———-(4) 5. x y pp? 1 ?x 4 ? = ? y 3 ? 7 x + 9 y = 11 ? 1A+1A 1A u? 1 x pp? 1 1A+1M+1A 1A y= u? 1 ———-(4) PP-DSE-MATH-CP 1? 4 ?????? FOR TEACHERSââ¬â¢ procedure ONLY ????? ??? ???????? ,?? ? ?? ,??? x= 4 5 1A 0. 8 4 5 ? ? ? 3x ? 7 x + 9 ? ? = 11 ? 4 ? ???????? ????? ??? 4 5 ????? ? ????? ??????????? ? ? ? 3x ? 7 x + 9 ? ? = 11 ? 4 ? 4 x= 5 1M 0. 8 ???????? ????? ?? ? ? 360 (1 + 30%) 80% = $ 585 ???? ?????????????????? ??? ? ? $ 585 ???????? ?? x (80%) 360 (1 + 30%) 360 (1 + 30%) 80% ? ? ? ? ???????? ,?? ? ?? ,??? ?? ,?? ???????? ?????? ??????? ,?? ? x y 3x + 1M 4 7 x + 9 y = 11 ?????? 6. (a) ? AOC = 337ð ? 157ð = 180ð A O FOR TEACHERSââ¬â¢ USE ONLY 1M C 1A (b) BO ? AC ? rudiment = 1 (13 + 15)(14) 2 = 196 1M 1A ———-(4) 7. 180ð ? 36ð 2 ? first rudiment = 72ð ? ABC = 1A u? 1 180ð ? 36ð 2 ? ACB = 72ð ? BCD = 90ð ? ACB = ?ACD = 90ð ? 72ð = 18ð ? ABD = ? ACD = 18ð 1A u? 1 ———-(4) PP-DSE-MATH-CP 1? 5 ?????? FOR TEACHERSââ¬â¢ USE ONLY ????? ? ? BAC = ? BDC = 36ð AB = AC ? ACB = ? ABC 1M 1M 1A ????? ?ABD = ? ABC ? CBD = 72ð ? 54ð = 18ð ? ? ?BCD = 90ð ? CBD = 180ð ? 90ð ? 36ð = 54ð ? BAC = ? BDC = 36ð AB = AC ? ACB = ? ABC 1A 1M 1M ?????? ?? ? AOC ??? ? ? ???? ? ?? ,?? ? ?? ,?? ?? , ?? ?? ? ?? ,?? ? ?? ,?? ?? , ?? ? ??? ???? ?? ??? ? ?? ??? ? ? ,?? ? ? ? ?????? 8. (a) FOR TEACHERSââ¬â¢ USE ONLY 1A ppââ¬1 1A P ppââ¬1 (b) ( x , y) ( x ? 3) 2 + ( y ? 4) 2 = ( x ? 5) 2 + ( y ? (? 2)) 2 1M+1A 1A A? B ? ? 3 + 5 4 + (? 2) ? =? , ? 2 ? 2 ? = (4 , 1) 1M A? B? 4 ? (? 2) = 3? 5 = ? 3 1A 1A ———-(5) 9. (a) =5? 5 =0 2? 2 1M 1A = 5? 2 =3 (b) 1A 1A ———-(5) PP-DSE-MATH-CP 1? 6 ?????? FOR TEACHERSââ¬â¢ USE ONLY ?????? ????? ? ,?? ? ? ? ,?? ? ?? ,?? ? ?? , ????????? ?? r =9 9 + 8 > 12 + s s 12 1A ———-(2) PP-DSE-MATH-CP 1? 8 ?????? FOR TEACHERSââ¬â¢ USE ONLY ?????? ?????? ? ??????? ,?? ????????????? ,?? ? ?? ????? ???? ,???? ??????? ,?? ? ?? 16 ? 2 2 = 7 km/h 7>6 = ???? 12 2 = 6 km/h ?? x 12 = 78 120 x = 7 . 8 ????? 78 : 120 = 63 ? 32 = 31 1M 1A u? 1 ———-(2) ?? ? ?????? ?????? ??????? ? ???????? ,?? ? ?????????? ? ??????? ?? ????? ?????? 13. (a) FOR TEACHERSââ¬â¢ USE ONLY pp? 1 n 6 3 = n 20 n = 40 1M k = 40 ? 6 ? 11 ? 5 ? 10 =8 (b) (i) 1M 1A ———-(3) 1M 1A u? 1 = (ii) m pp? 1 1M 1A ———-(4) PP-DSE-MATH-CP 1? 9 ??????FOR TEACHERSââ¬â¢ USE ONLY ?????? ??? ?????????? ?????????????? ,??? ?? ?? 5 + m (45)(2) = 40 + m 360 20 + 4m = 40 + m 3m = 20 20 3 ??????? ????? 5 (360ð) 40 = 45ð ??????? ?? 5+m n+m ? ????????????????????????? ??????? ? ???????? ? ? ???? ?????? 14. (a) ? BCD ~ ? OA D FOR TEACHERSââ¬â¢ USE ONLY 2A ———-(2) 1M 1M (b) (i) (b) 1M AD CD ( 0 , 4) ppââ¬1 1M 1M (ii) AC OABC (3 , 2 ) OABC OABC k1 k2 ?0 + 0 + k1 (0) + k 2 (0) + k3 = 0 ? ? 2 2 ? 6 + 0 + k1 (6) + k 2 (0) + k3 = 0 ? 2 2 ? 0 + 4 + k1 (0) + k 2 (4) + k 3 = 0 ? 2 2 1M 1A ———-(7) OABC x + y ? 6x ? 4 y = 0 PP-DSE-MATH-CP 1? 10 ?????? FOR TEACHERSââ¬â¢ USE ONLY 2 2 ????? k1 = ? 6 k 2 = ? 4 k3 = 0 ? ? ? ? ?? , x + y + k1 x + k 2 y + k3 = 0 k3 ????? 2 2 ? ( x ? 3) 2 + ( y ? 2) 2 = 13 ? (3 ? 0) + (4 ? 2) 2 = 13 2 1A x 2 + y 2 ? 6x ? 4 y = 0 1M ? ? ?? ? ? ? ? ???? ???? ??? ???? ? ,?? ?????? ,?? ? ????????? ,?? ????? ?? ?? ? ? ,?? ? ???? ? ,?? ? ?? ,??? ) ?? ( ??? h 2 ? 24h + 80 = 0 h=4 h = 20 C 1A ( ) ????? ? ? ? 12 ? h ? ? 2 2 ? 6 + 12 ? ? = 16 ? 45 ? 2 ??????? ? ?? , ? ???? ? ? C (0 , h) 16 ? CD ? ? ? = 45 ? AD ? 2 ?? ? ? ?????? 15. (a) FOR TEACHERSââ¬â¢ USE ONLY s 36 ? 48 = ? 2 s s=6 1M 66 ? 48 6 =3 = 1A ———-(2) (b) 1 ———-(2) PP-DSE-MATH-CP 1? 11 ??????FOR TEACHERSââ¬â¢ USE ONLY ?????? 1M 1A ???? ?? ? ?????????? ,?? ????????? ,?? ?????? ,?? ? ? ??????? ,????????????????? ???????????? ,?? ?????????????????? ???????????? ? ? ?????????? ?????? 16. (a) FOR TEACHERSââ¬â¢ USE ONLY = 1M 1A = 1A ———-(2) 0. 112 (b) 1M 1A = = = 30 C4 1M 1A 1M 1A 1M 1A ———-(2) = 530 609 PP-DSE-MATH-CP 1? 12 ?????? FOR TEACHERSââ¬â¢ USE ONLY ??????? ??? ??? ? 18 ?? 12 ?? 11 ?? 10 ? ? 18 ?? 17 ?? 12 ?? 11 ? ? 18 ? ? 17 ?? 16 ? ? 12 ? = 4 ? ?? ?? ?? ? + 6 ? ?? ?? ?? ? + 4 ? ? ? ?? ? ? ? ? 30 ?? 29 ?? 28 ?? 27 ? ? 30 ?? 29 ?? 28 ?? 27 ? ? 30 ? ? 29 ?? 28 ? ? 27 ? ??????? ? 68 ? 2 ?? 11 ?? 10 ?? 9 ? ? ? ? ? ?? ?? ? 609 ? 30 ?? 29 ?? 28 ?? 27 ? 530 = 609 = 1? ??????? 530 609 ??? ??? 18 12 18 12 18 12 C1 C3 + C 2 C2 + C3 C1 ??????? 530 609 ? = 1? 12 68 C4 ? 30 609 C 4 1 â⬠(a) â⬠p1 0. 870 3 0. 870 1 â⬠(a) â⬠p2 0. 870 14 0. 870 , ??????? ? ? 18 ?? 17 ?? 16 ?? 15 ? = ? ?? ?? ?? ? ? 30 ?? 29 ?? 28 ?? 27 ? 68 = 609 1M ??????? 68 609 ?????? 0. 112 ? r ?? r ? 1 ?? r ? 2 ?? r ? 3 ? ? ?? ? n ?? n ? 1 ?? n ? 2 ?? n ? 3 ? ?? ?? ? ? ?? ?? ?? ? 18 C4 30 C4 ?? r 9 000 000 1 ? 0 . 8 (0. 8) n < 0. 1 n record 0. 8 < log 0. 1 n> log 0. 1 log 0. 8 n > 10. 31885116 11 n 1M 1A (ii) 1A (iii) = ( ( ) 1M )( ) 1M 1A ———(10) PP-DSE-MATH-CP 1? 16 ?????? FOR TEACHERSââ¬â¢ USE ONLY ?????? ? 2 000 000 (1 ? (0. 8) m ) 4 000 000 (1 ? (0. 64) m ) ? 0 m (0. 8) ? 1 < 0 m ?????? ????? ? 2 000 000(1 ? (0. 8) m ) 4 000 000(1 ? (0. 64) m ) ? 1 ? 0 . 8 1 ? 0. 64 10 ? ? = 10 000 000 ? (1 ? (0. 8) m ) ? (1 ? (0. 64) m ) ? 9 ? ? 10 ? ? = 10 000 000 ? (1 ? (0. 8) m ) ? (1 ? (0 . 8) 2m ) ? 9 ? ? 10 000 000 m 2 m = 10 ((0. 8) ) ? 9(0. 8) ? 1 9 10 000 000 = 10 (0. 8) m + 1 (0. 8) m ? 1 9 m (0. 8) m > 0 (0. 8) m < 1 1M ?????? < 2 000000 + 2 000000(1 ? 20%) + 2 000000(1 ? 20%)2 + L 2 000 000 = 1 ? 0. = 10 000 000 $ 10 000 000 1M ??????? ??? 2 000000 + 2 000000(1 ? 20%) + L + 2 000000(1 ? 20%)n? 1 > 9 000000 ????? ?????? $ 9 000 000 ?? ? ? ? ??????????? ???? ??????????? ,?? ??????? ,?? ?? ,?? ? ?? ,?? ?? , ?????? ??????? ? ??????? ,?? ?????????? ? ? ?????? FOR TEACHERSââ¬â¢ USE ONLY ???????? ???????? ??? ?? ???? ??? 1. 2. 3. 4. 5. A C A D D 31. 32. 33. 34. 35. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. C B D A B D A A B C D C A D C C B C D B D B A B C 36. 37. 38. 39. 40. 41. 42. 43. 44. 45. ?????? FOR TEACHERSââ¬â¢ USE ONLY ?? D B C D A B A C A C B A B D C ?? ?? ??\r\n'
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment